The dimension of P = frac{{{B^2}{l^2}}}{ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$F = BIL$
$	herefore \,\,{m{Dimension}}\,{m{of}}\,{m{[}}B{m{]}} = \frac{{{m{[}}F{m{]}}}}{{{m{[}}I{m{]}}\,{m{[}}L{m{]}}}} = \frac

Vedclass · Accepted Answer

$M{L^2}{T^{ - 4}}I^{-2}$

Vedclass · Answer

$F = BIL$
$	herefore \,\,{m{Dimension}}\,{m{of}}\,{m{[}}B{m{]}} = \frac{{{m{[}}F{m{]}}}}{{{m{[}}I{m{]}}\,{m{[}}L{m{]}}}} = \frac{{[ML{T^{ - 2}}]}}{{[I]\,[L]}}$=$[M{T^{ - 2}}{I^{ - 1}}]$
$[P] = \frac{{{B^2}{l^2}}}{m} = \frac{{{{[M{T^{ - 2}}{I^{ - 1}}]}^2} 	imes [{L^2}]}}{{[M]}}$ $ = [M{L^2}{T^{ - 4}}{I^{ - 2}}]$

The dimension of $P = \frac{{{B^2}{l^2}}}{m}$ is
where $B=$ magnetic field, $l=$ length, $m =$ mass

Similar Questions

Dimensions of coefficient of viscosity are

Which one of the following does not have the same dimensions

The dimensions of resistivity in terms of $M,\,L,\,T$ and $Q$ where $Q$ stands for the dimensions of charge, is

The physical quantity which has the dimensional formula ${M^1}{T^{ - 3}}$ is

The dimensional formula for the modulus of rigidity is

The dimension of $P = \frac{{{B^2}{l^2}}}{m}$ is where $B=$ magnetic field, $l=$ length, $m =$ mass